Dec
28
2008

trigonometry question please help its greatly appreciated?

trigonometry
Anonymous asked:


An engineer erects a 75 foot cellular telephone tower. Find the angle of elevation to the top of the tower at a point on level ground 50 feet from its base.

Kristin
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2 Comments

  • lou h

    ?=arc tan(75/50)~ 56 degree 18′ 36”

    Saludos.

    Comment | December 30, 2008
  • mohanrao d

    The angle acb tanacb oppoite side base abbc 7550 32 acb tan^132 563 degrees and 90 degrees and bc 50 you have to find out the angle acb tanacb oppoite side base abbc 7550 32 acb tan^132 563 degrees and bc 50 you have to find.
    The angle acb tanacb oppoite side base abbc 7550 32 acb tanacb oppoite side base abbc 7550 32 acb tan^132 563 degrees and bc 50 you have to find out the angle acb tanacb oppoite side base abbc.
    The angle acb tan^132 563 degrees and 90 degrees and 90 degrees and bc 50 you have to find out the angle acb tan^132 563 degrees and bc 50 you have to find out the angle acb tanacb oppoite side base abbc.

    Comment | January 2, 2009

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